How do you simplify $arcsin (sin (\frac{π}{8}))$ $arcsin(sin(pi/8))$ ?

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Answer 1 · 2016-07-31T05:14:48

$\frac{π}{8}$ $pi/8$

Use $f^{- 1} f (x) = x$ $f^(-1)f(x)=x$

Here, $arcsin$ $arcsin$ is $f^{- 1}$ $f^(-1)$ and $sin$ $sin$ is $f$ $f$ . The operand $x = \frac{π}{8}$ $x = pi/8$ .

How do you simplify arcsin(sin(pi/8))arcsin(sin(π8))arcsin(sin(pi/8))?