How do you solve the following equation $2 cos x - 1 = 0$ $2 cos x - 1=0$ in the interval [0, 2pi]?

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Answer 1 · 2016-07-31T09:59:23

The solutions are $x = \frac{π}{3} and x = 5 \frac{π}{3}$ $x=pi/3 and x=5pi/3$

$2 cos (x) - 1 = 0$ $2cos(x)-1=0$

Get rid of -1 from left side

$2 cos (x) = 1$ $2cos(x)=1$

$cos (x) = \frac{1}{2}$ $cos(x)=1/2$

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Use the unit circle Finds the value of x, where cos(x)=1/2.

It is clear that for #x=pi/3 and x=5pi/3. cos (x)=1/2.

so the solutions are $x = \frac{π}{3} and x = 5 \frac{π}{3}$ $x=pi/3 and x=5pi/3$

How do you solve the following equation 2 cos x - 1=02cosx−1=0 2 cos x - 1=0 in the interval [0, 2pi]?