How do you find #f(-1)# given #f(n)=-3n^2-4n #?
2 Answers
Aug 3, 2016
Just put -1 in n's place.
Explanation:
f(n)= -3n^2-4n
= -3(-1)^2 - 4(-1)
= -3(1) +4
= -3+4 = 1
Aug 3, 2016
f( -1) = 1
Explanation:
Given f(n) then f(-1) means assign the value -1 to n. That is substitute n = -1 into the function.
#f(n)=-3n^2-4n#
#rArrf(-1)=-3(-1)^2-4(-1)=-(3xx1)-(4xx-1)#
#=-3-(-4)=-3+4=1#