Question

How do you factor `x^3y^3 - 8`?

Answer 1

`=(xy-2)(x^2y^2+2xy+2)`

Explanation:

`x^3y^3-8`
or
`(xy)^3-2^3`
Since `a^3-b^3=(a-b)(a^2+ab+b^2)`
or
`=(xy-2)((xy)^2+2xy+2)`
`=(xy-2)(x^2y^2+2xy+2)`