How do you do titration problems to find molarity?

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How do you do titration problems to find molarity?

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Answer 1 · 2016-08-07T21:55:21

See below.

Explanation:

Titration is used to determine the unknown molarity ( $M$ $M$ ) of a solution (called analyte) using a titrant, which is a solution of known concentration.

Considering the analyte is an acidic solution (unknown molarity) and that it will be titrated using a basic solution with a known molarity (assuming monoprotic acid and base).

At the equivalence point, the number of mole of $H^{+}$ $H^+$ ions will be equal to the number of mole of $O H^{-}$ $OH^-$ ions:

$n_{H^{+}}^{+} = n_{O H^{-}}^{-}$ $n_(H^+)=n_(OH^-)$

Note that the relationship between molarity and number of mole is:

$M = \frac{n}{V}$ $M=n/V$ where $V$ $V$ is the volume of the solution.

Thus, $n = M \times V$ $n=MxxV$ .

Therefore, $M_{a} \times V_{a} = M_{b} \times V_{b}$ $M_(a)xxV_(a)=M_(b)xxV_(b)$

$\Rightarrow M_{a} = \frac{M_{b} \times V_{b}}{V_{a}}$ $=>M_(a)=(M_(b)xxV_(b))/(V_(a))$

Here is a video that fully explains this topic:
Lab Demonstration | Acid - Base Titration.

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How do you do titration problems to find molarity?

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