Question

How do you solve `(2x)/(4-x)=x^2/(x-4)`?

Answer 1

`x=0`
`x=-2`

Explanation:

`(2x)/(4-x)=x^2/(x-4)`
or
`-(2x)/(x-4)=x^2/(x-4)`
or
`x^2=-2x`
or
`x^2+2x=0`
or
`x(x+2)=0`
or
`x=0`------------------Ans `1`
or
`x+2=0`
or
`x=-2`----------------------------Ans `2`