The length of a rectangle is 5 cm more than twice its width. What is the largest possible width if the perimeter is at most 64 cm?

1 Answer
Aug 13, 2016

#width=9cm#

Explanation:

Perimeter of a rectangle#=2(a+b)# where #a# is the length and #b# is the width
As given we can write
#a=2b+5# by plugging this value

Perimeter of a rectangle#64=2(a+b)#
or
#a+b=64/2#
or
#a+b=32#
or
#2b+5+b=32#
or
#3b=32-5#
or
#3b=27#
or
#b=27/3#
or
#b=9#