Question

How do you evaluate the limit `e^xcosx` as x approaches `0`?

Answer 1

You can plug `x = 0` in and solve this with hardly any work.

`color(blue)(lim_(x->0) e^xcosx)`

`= e^0cos(0)`

`= 1*1 = color(blue)(1)`

Answer 2

1

Explanation:

`lim_(xrarr0)e^xcosx = e^0cos(0) = 1*1 = 1`