What is the molarity for 23.4 g of sodium hydroxide in 250.0 mL?

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Answer 1 · 2016-08-17T18:28:33

$"2.34 M"$

The molecular weight of sodium hydroxide is $"39.997 g/mol"$ . That is, 1 mole weights $"39.997 g"$ .

You have $"23.4 g"$ , so you have

$(23.4cancel("g"))/(39.997cancel("g")/"mol") = "0.585 moles"$ .

These $0.585$ moles are present in $"250 ml"$ , and $"250 ml"$ is equivalent to $0.25$ liters.

Molarity is moles per liter.

$"molarity" = "moles" / "litre"$

$"molarity" = "0.585 moles" / "0.25 L"$

$"molarity " = " 2.34 M"$

Here is a blog post on moles and molarity you might like to look at.