Question

For what values of x, if any, does `f(x) = 1/((x-3)(x-2))` have vertical asymptotes?

Answer 1

`x=3 & 2`

Explanation:

`f(x)` is undefined or approaches infinity when the denominator is zero.

In this case, for a zero denominator:
Either factor `(x-3)` or factor `(x-2)` equals to zero.

Hence `x=3&2` will give you vertical asymptotes.