What is the equation of the line passing through $(3,-5)$ and $(42,1)$ ?

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Answer 1 · 2016-08-24T16:29:57

Both points satisfy the line equation $y=mx+b$ , so you need to find $m$ and $b$

Since both points satisfy the equation, we know that:

$-5=m*3+b$ , and

$1=m*42+b$

We now have a system of two equations with $m$ and $b$ . To solve it we can subtract the first from the second equation to eliminate $b$ :

$6=39m$ and so $m=6/39=2/13$ . From the first equation now we have:

$-5-(2/13)*3=b$ , and so $b=-65/13-6/13=-71/13$ .

The equation of the line is then:

$y=2/13x-71/13$

What is the equation of the line passing through (3,-5)(3,-5) and (42,1)(42,1)?