Question

How do you find the slope that is perpendicular to the line `-5x-3y+8=0`?

Answer 1

The slope of one line and the slope of a line perpendicular to the first line are negative inverses of each other.

Explanation:

If Line1 has slope `m = 3` , then perpendicular Line2 will have slope `m = -1/3`

To find the slope of your line `−5x−3y+8=0`, let's put the equation in slope-intercept form:

`y = - (5/3)x + 8/3`

So, your line has slope `m =- 5/3`.

The slope of a line that is perpendicular to your line above will be the negative inverse, that is:

`(-1)/(-5/3)` , which equals positive `3/5` .

(It's the lines that are perpendicular to each other, not the slopes. The slopes are negative inverses.)