Question #cdaba

1 Answer
Aug 28, 2016

b~~10.0427613b10.0427613
/_A ~~ 36.861347637786^oA36.861347637786o
/_C ~~ 66.8053193213^oC66.8053193213o

Explanation:

The Cosine Law states how one side of a triangle can be expressed using two other sides and angle between them.

Also recall the measurement of angles in degrees, minutes and seconds:
1^o1o is 1/360^(th)1360th part of a full circle;
1' = 1/60^(th) of 1^o
1" = 1/60^(th) of 1'

The Cosine Law:
enter image source here

In our case we will use the following form:
b^2 = c^2+a^2-2cacosB

Using exact values,
b^2 = 9.5^2 + 6.2^2 - 2*9.5*6.2*cos(76^o20')

According to calculator,
cos(76^o20') = 0.23627288165

Therefore,
b^2 = 9.5^2 + 6.2^2 - 2*9.5*6.2*0.23627288165=
=100.85705454163

Hence, b~~10.0427613

Using the same Law of Cosines, we can find two other angles:

cos A = (-a^2+b^2+c^2)/(2bc)=
=(-6.2^2+10.0427613^2+9.5^2)/(2*10.0427613*9.5)~~0.800089526

Therefore, /_A=arccos(0.800089526)=0.643351883 (rad)
/_A=36.861347637786^o

cos C = (-c^2+a^2+b^2)/(2ab)=
=(-9.5^2+6.2^2+10.0427613^2)/(2*6.2*10.0427613)=0.39385658039

Therefore, /_C=arccos(0.39385658039)=1.16597277 (rad)
/_C=66.8053193213^o