How do you evaluate ${log}_{8} 2$ $log_8 2$ ?

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Answer 1 · 2016-09-03T00:50:41

Start by remembering that the log function is the inverse of the exponential function.

${log}_{2} 8 = y \Rightarrow 2^{y} = 8$ $log_2 8 = y => 2^y = 8$

2 is the base of the logarithm, and of the exponential also.

2 raised to what power equals 8?

$2^{3} = 8$ $2^3 = 8$ , right?

So, ${log}_{2} 8$ $log_2 8$ equals 3.

Answer 2 · 2016-09-03T01:02:17

$\frac{1}{3}$ $1/3$

${log}_{8} 2 = x$ $log _"8"2 = x$

$8^{x} = 2$ $8^x=2$

$x = \frac{1}{3}$ $x=1/3$

How do you evaluate log_8 2log82log_8 2?