How do you find another point on each line using slope and point given m=2/5; passes through (1,-4)?

1 Answer
Sep 4, 2016

You have to use the equation of the straight line with slope #m# and intercept #b#, #y=mx+b#

Explanation:

Since #m=2/5# is given, the equation of the straight line given is #y=2/5x+b#, where we have to still find #b#. But we know that the line passes through the point #(1,-4))#, so the coordinates of the point satisfy the line equation. That is:

#-4=2/5 *1 +b#, and from this we know that #b=-4-2/5=-22/5#

Thus the line equation is

#y=2/5x-22/5#, and any point which coordinates satisfy the equation is on the line. For example if #x=2# then #y=2/5 * 2 -22/5=-18/5#, so we know that the point #(2, -18/5)# is also on the line. Similarly #(3,-16/5)# is on the line, etc.