Since m=2/5m=25 is given, the equation of the straight line given is y=2/5x+by=25x+b, where we have to still find bb. But we know that the line passes through the point (1,-4))(1,−4)), so the coordinates of the point satisfy the line equation. That is:
-4=2/5 *1 +b−4=25⋅1+b, and from this we know that b=-4-2/5=-22/5b=−4−25=−225
Thus the line equation is
y=2/5x-22/5y=25x−225, and any point which coordinates satisfy the equation is on the line. For example if x=2x=2 then y=2/5 * 2 -22/5=-18/5y=25⋅2−225=−185, so we know that the point (2, -18/5)(2,−185) is also on the line. Similarly (3,-16/5)(3,−165) is on the line, etc.
