How do you solve $3x - 8+ 4x > 6$ ?

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Answer 1 · 2016-09-10T03:33:07

$x > 2$

$3x - 8 +4x >6$

Group the common terms together

$7x - 8 >6$

Add 8 on both sides

$7x > 14$

Divide 7 on both sides

$x >2$

How do you solve 3x - 8+ 4x > 63x - 8+ 4x > 6?