120 grams $N a C l$ $NaCl$ is equal to how many molecules of $N a C l$ $NaCl$ ?

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120 grams $N a C l$ $NaCl$ is equal to how many molecules of $N a C l$ $NaCl$ ?

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Answer 1 · 2016-09-15T19:09:59

$1.24 \cdot 10^{24}$ $1.24 * 10^24$ formula units

Explanation:

$NaCl$ $"NaCl"$ is an ionic compound, so there are no molecules, only formula units.

$1 mol of NaCl = 6.02 \cdot 10^{23} formula units$ $"1 mol of NaCl" = 6.02 * 10^23 " formula units"$

$Formula units NaCl = 120 g NaCl \cdot \frac{1 mol NaCl}{58.44 g NaCl} \cdot \frac{6.02 \cdot 10^{23} formula units}{1 mol NaCl}$ $"Formula units NaCl" = "120 g NaCl" * "1 mol NaCl"/"58.44 g NaCl" * (6.02 *10^23 " formula units")/"1 mol NaCl"$

$= 1.24 \cdot 10^{24} formula units$ $= 1.24 * 10^24 " formula units"$

Note: 58.44 g/mol is the molecular weight of $NaCl$ $"NaCl"$

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120 grams $N a C l$ $NaCl$ is equal to how many molecules of $N a C l$ $NaCl$ ?

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120 grams $N a C l$ $NaCl$ is equal to how many molecules of $N a C l$ $NaCl$ ?