How do you solve $2 (5 - 3 v) + 9 v = 28$ $2( 5- 3v ) + 9v = 28$ ?

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Answer 1 · 2016-09-20T20:55:56

try to leave v on the one side alone...

$(2 \cdot 5 - 2 \cdot 3 v) + 9 v = 28$ $(2*5 -2*3v) +9v = 28$
$10 - 6 v + 9 v = 28$ $10-6v+9v=28$
$- 6 v + 9 v = 28 - 10$ $-6v+9v = 28-10$

$3 v = 18 \Rightarrow v = \frac{18}{3} = 6$ $3v=18 => v=18/3 = 6$

How do you solve 2(5−3v)+9v=282( 5- 3v ) + 9v = 28?