Question

How do you solve `11w + 2( 3w - 1) = 15w`?

Answer 1

`w=1`

Explanation:

1) start off writing `11w + 2(3w - 1) = 15w`
2) distribute the `2` to the `(3w - 1)`
-you then get `6w - 2` because `2(3) = 6 and 2(-1) = -1`
3) now write `11w+6w-2=15w`
4) add `11w and 6w` to get `17w`
5) now you have `17w-2=15w`
6) subtract `17w` from both sides to get `w` on its own side
7) you now have `-2=-2w`
8) divide each side by `-2` to get `w` by itself

work:

`11w+2(3w-1)=15w`
`11w+6w-2=15w`
`17w-2=15w`
`-2=-2w`
`1=w`

to check, plug in `1` for `w`

`11(1)+2(3(1)-1)=15(1)`
`11+2(3-1)=15`
`11+2(2)=15`
`11+4=15`
`15=15`