The mass of a diamond is $1.76$ $1.76$ $g$ $g$ . The volume is $0.5$ $0.5$ $c m^{3}$ $cm^3$ . What is the density of the diamond?

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Answer 1 · 2016-09-21T01:33:25

$3.5 \frac{g}{c m^{3}}$ $3.5 g/(cm^(3))$

To calculate the density, we'll use the formula below:
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Usually, density will have units of $\frac{g}{m L}$ $g/(mL)$ when dealing with a liquid or units of $\frac{g}{c m^{3}}$ $g/(cm^3)$ when dealing with a solid.
The mass has units of grams, $g$ $g$ .
The volume can have units of $m L$ $mL$ or $c m^{3}$ $cm^3$

We are given the mass and the volume, both of which have good units. All we have to do is plug the given values into the equation:

$D e n s i t y = \frac{1.76 g}{0.5 c m^{3}}$ $Density =(1.76 g)/(0.5cm^3)$

Therefore the diamond has a density of $3.5 \frac{g}{c m^{3}}$ $3.5 g/(cm^3)$ .

The mass of a diamond is 1.761.761.76 ggg. The volume is 0.50.50.5 cm^3cm3cm^3. What is the density of the diamond?