How do you evaluate $sec ({sec}^{- 1} (\frac{1}{3}))$ $sec(sec^-1(1/3))$ ?

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How do you evaluate $sec ({sec}^{- 1} (\frac{1}{3}))$ $sec(sec^-1(1/3))$ ?

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Answer 1 · 2016-09-21T02:25:08

You can't, at least not with real numbers.

Explanation:

The expression ${sec}^{- 1} (\frac{1}{3})$ $sec^{-1}(1/3)$ means find $x$ $x$ so that $sec x = \frac{1}{3}$ $sec x=1/3$ . But for all real numbers $x$ $x$ , $sec x = \frac{1}{cos x}$ $sec x=1/(cos x)$ has an absolute value greater than or equal to $1$ $1$ .

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How do you evaluate $sec ({sec}^{- 1} (\frac{1}{3}))$ $sec(sec^-1(1/3))$ ?

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How do you evaluate $sec ({sec}^{- 1} (\frac{1}{3}))$ $sec(sec^-1(1/3))$ ?