How do you solve $\frac{n - 12}{n + 1} = - \frac{6}{5}$ $\frac{n - 12}{n + 1} = - \frac{6}{5}$ ?

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Answer 1 · 2016-09-23T08:06:54

$n = \frac{54}{11}$ $n=54/11$

$\frac{n - 12}{n + 1} = \frac{- 6}{5}$ $(n-12)/(n+1)=(-6)/5$

Cross multiply

$\Rightarrow (n - 12) \times 5 = (n + 1) \times - 6$ $=>(n-12)xx5=(n+1)xx-6$

$\Rightarrow 5 n - 60 = - 6 n - 6$ $=>5n-60=-6n-6$

$\Rightarrow 5 n - 60 + 6 n = - 6 n - 6 + 6 n$ $=>5n-60 color(red)(+6n)=-6n-6color(red)(+6n)$

$\Rightarrow 11 n - 60 = - 6$ $=>11n-60=-6$

$\Rightarrow 11 n - 60 + 60 = - 6 + 60$ $=>11n-60color(red)(+60)=-6color(red)(+60)$

$\Rightarrow 11 n = 54$ $=>11n=54$

$\Rightarrow n = \frac{54}{11}$ $=>n=54/11$

How do you solve \frac{n - 12}{n + 1} = - \frac{6}{5}n−12n+1=−65\frac{n - 12}{n + 1} = - \frac{6}{5}?