How do you multiply #(4n - 1) ( 3n + 4)#?
2 Answers
Explanation:
start off by writing out
multiply by distributing
so far you have
now distribute again but with the -1
you now have
subtract like terms
put it together and you have:
Use FOIL to find:
#(4n-1)(3n+4) = 12n^2+13n-4#
Explanation:
If you find it helpful, you can use the FOIL ("First", "Outside", "Inside", "Last") mnemonic to help to combine all the required terms:
#(4n-1)(3n+4) = overbrace((4n*3n))^"First"+overbrace((4n*4))^"Outside"+overbrace(((-1)*3n))^"Inside"+overbrace(((-1)*4))^"Last"#
#color(white)((4n-1)(3n+4)) = 12n^2+16n-3n-4#
#color(white)((4n-1)(3n+4)) = 12n^2+13n-4#
FOIL can be used when multiplying any two binomials.