How do you solve #8- 6( 1- 7b ) = - 82#?

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Answer 1 · 2016-09-24T17:32:35

Multiply first then isolate #b#.

Multiply #8-6# and #(1-7b)#. You must get #8-56b-6+42b#.

Simplify. This will then be: #2-14b#.

It will look like: #2-14b=-82#

Isolate #b#

#-14b=-82-2#

Divide by #-14# both sides.

Then:

#b=-84/-14#

And #b=6#.