How do you simplify $- 2 \sqrt{3 b} + \sqrt{27 b}$ $-2sqrt(3b)+sqrt(27b)$ ?

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Answer 1 · 2016-09-25T12:17:58

$\sqrt{3 b}$ $sqrt(3b)$

$- 2 \sqrt{3 b} + \sqrt{9 \cdot 3 b} = - 2 \sqrt{3 b} + \sqrt{9} \cdot \sqrt{3 b}$ $-2sqrt(3b)+sqrt(9*3b) = -2sqrt(3b)+sqrt(9)*sqrt(3b)$

$- 2 \sqrt{3 b} + 3 \sqrt{3 b} = 3 \sqrt{3 b} - 2 \sqrt{3 b} = (3 - 2) \sqrt{3 b}$ $-2sqrt(3b)+3sqrt(3b) = 3sqrt(3b)-2sqrt(3b) = (3-2)sqrt(3b)$

$= \sqrt{3 b}$ $=sqrt(3b)$

How do you simplify −2√3b+√27b-2sqrt(3b)+sqrt(27b)?