How do you solve #5k ( 6- 6m)# for #k=2# and #m=1/2#?

1 Answer
Beaker M.
Sep 26, 2016

So, let's take a look at the equation we have.
#5k(6-6m)# for #k=1# and #m=1/2#

So, let's first space this out a bit.
#5*k*(6-(6*m)) #

Now, since they want us to solve it as if #k=1# and #m=1/2#, we should substitute any mention of #k# with #1# and any mention of #m# with #1/2#. Our new, substituted equation is:

#5*1*(6-(6*1/2))#

Now, we start to solve.

#5*1*(6-(6/2))# Multiplied 6 times 1/2 to get 6/2

#5*1*(6-(3))# Simplified 6/2 to 3

#5*1*(3)# Subtracted 3 from 6

#5*3# Multiplied 3 and 1

#15#

Cheers!

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