How do you solve $4 \leq 2 x + 2 < 12$ $4\leq 2x + 2< 12$ ?

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Answer 1 · 2016-09-28T16:39:54

$1 \leq x < 5$ $1<=x<5$ or as an interval: $x \in < 1; 5)$ $x in <1;5)$

Perform subtraction by 2 on each of the three parts and get

$2 \leq 2 x < 10$ $2 <=2x<10$

Divide each part by 2 and get

$1 \leq x < 5$ $1<=x<5$

How do you solve 4≤2x+2<124\leq 2x + 2< 12?