What is the Cartesian form of $(- 1, \frac{14 π}{3}))$ $(-1,(14pi)/3))$ ?

Question

What is the Cartesian form of $(- 1, \frac{14 π}{3}))$ $(-1,(14pi)/3))$ ?

1 Answer

Impact of this question

1757 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-01T03:36:43

$(x, y) = (\frac{1}{2}, - \frac{\sqrt{3}}{2})$ $(x,y) = (1/2, -sqrt3/2)$

Explanation:

$x = r cos (θ)$ $x = r cos(theta)$

$= (- 1) cos (\frac{14 π}{3})$ $= (-1) cos((14pi)/3)$

$= - cos (\frac{2 π}{3})$ $= -cos((2pi)/3)$

$= - (- \frac{1}{2})$ $= -(-1/2)$

$= \frac{1}{2}$ $= 1/2$

$y = r sin (θ)$ $y = r sin(theta)$

$= (- 1) sin (\frac{14 π}{3})$ $= (-1) sin((14pi)/3)$

$= - sin (\frac{2 π}{3})$ $= -sin((2pi)/3)$

$= - \frac{\sqrt{3}}{2}$ $= -sqrt3/2$

Science

Math

Humanities

... and beyond

What is the Cartesian form of $(- 1, \frac{14 π}{3}))$ $(-1,(14pi)/3))$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

What is the Cartesian form of (−1,14π3))(-1,(14pi)/3))?

1 Answer

Explanation:

Related questions

Impact of this question

What is the Cartesian form of $(- 1, \frac{14 π}{3}))$ $(-1,(14pi)/3))$ ?