How do you simplify $\sqrt{98x^{4} y^{6} z^{2}}$ ?

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Answer 1 · 2016-10-02T01:08:38

$7 sqrt(2) x^(2) y^(3) z$

We have: $sqrt(98 x^(4) y^(6) z^(2))$

Let's express $98$ as a product:

$= sqrt((14 cdot 7) x^(4) y^(6) z^(2))$

$= sqrt((2 cdot 7 cdot 7) x^(4) y^(6) z^(2))$

$= sqrt(2 cdot 7^(2) x^(4) y^(6) z^(2))$

$= sqrt(2) cdot 7 cdot x^(2) cdot y^(3) cdot z$

$= 7 sqrt(2) x^(2) y^(3) z$

Answer 2 · 2016-10-31T13:47:49

Answer is $sqrt(98x^4y^6z^2$ $=$ $7sqrt(2)x^2y^3z$ .

$sqrt(98x^4y^6z^2$ $=sqrt(49*2*(x^2)^2*y^2*(y^2)^2*z^2$ $=7sqrt(2)x^2y^3z$ . (answer).

How do you simplify \sqrt{98x^{4} y^{6} z^{2}}\sqrt{98x^{4} y^{6} z^{2}}?