How do you evaluate the definite integral $int (1/x) dx$ from $[1,2]$ ?

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Answer 1 · 2016-10-03T01:16:59

$ln2 ~= 0.69315$

$int_1^2 1/x dx = lnx]""_1^2$ Standard integral

$= ln2-ln1 = ln2 -0$

$=ln2 ~= 0.69315$

How do you evaluate the definite integral int (1/x) dxint (1/x) dx from [1,2][1,2]?