Question

How do you evaluate `log_15 (1/225)`?

Answer 1

`log_15 (1/225)=-2`

Explanation:

`log_2 8=3` is another way of writing `2^3=8`
That is the easy one to remember!!
So `log_15 (1/225)=x` is the same thing as `15^x=(1/225)`

`15^x=(1/15^2)`
`15^x=15^-2`
So `x=-2`