How do you evaluate ${log}_{15} (\frac{1}{225})$ $log_15 (1/225)$ ?

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How do you evaluate ${log}_{15} (\frac{1}{225})$ $log_15 (1/225)$ ?

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Answer 1 · 2016-10-04T07:28:03

${log}_{15} (\frac{1}{225}) = - 2$ $log_15 (1/225)=-2$

Explanation:

${log}_{2} 8 = 3$ $log_2 8=3$ is another way of writing $2^{3} = 8$ $2^3=8$
That is the easy one to remember!!
So ${log}_{15} (\frac{1}{225}) = x$ $log_15 (1/225)=x$ is the same thing as $15^{x} = (\frac{1}{225})$ $15^x=(1/225)$

$15^{x} = (\frac{1}{15^{2}})$ $15^x=(1/15^2)$
$15^{x} = 15^{- 2}$ $15^x=15^-2$
So $x = - 2$ $x=-2$

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How do you evaluate ${log}_{15} (\frac{1}{225})$ $log_15 (1/225)$ ?

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How do you evaluate ${log}_{15} (\frac{1}{225})$ $log_15 (1/225)$ ?