How do you differentiate $f (x) = cos (x^{2} - x)$ $f(x)=cos(x^2-x)$ using the chain rule?

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Answer 1 · 2016-10-07T00:06:50

$f' (x) = - sin (x^{2} - x) \cdot (2 x - 1)$ $f'(x)=-sin(x^2-x)*(2x-1)$

When you use the Chain Rule you take the derivative of the "outside" and then the derivative of the "inside".

$f' (x) = - sin (x^{2} - x) \cdot (2 x - 1)$ $f'(x)=-sin(x^2-x)*(2x-1)$

Click on the video below to see another example of using the Chain Rule.

How do you differentiate f(x)=cos(x2−x)f(x)=cos(x^2-x) using the chain rule?