How do you solve #-3/7x+4/7=2#?

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Answer 1 · 2016-10-07T00:23:22

#x=10/-3#

Remove the denominators by multiplying each term by 7.

#cancel(7)(-3/cancel7x)+(cancel7)(4/cancel7)=(7)2#

#-3x+4=14#

Add -4 to both sides

#-3x+4color(red)(-4)=14color(red)(-4)#

#-3x=10#

isolate x by dividing by -3

#cancel(-3)/cancel(-3)x=10/-3#

#x=10/-3#