How do you simplify $\log_{5} ( b^{2} a^{8} )$ ?

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Answer 1 · 2016-10-07T22:33:04

Please follow the instructions below...

Because of logarithmic rules, which can be seen on this page http://mathsvideos.net/log-formulas/, what you see below is true.

$log_5(b^2a^8)$

$=log_5((ba^4)^2)$

$=2log_5(ba^4)$

$=2{log_5(b)+log_5(a^4)}$

$=2{log_5(b)+4log_5(a)}$

$=2log_5(b)+8log_5(a)$

You can find out why the above transformations are mathematically coherent by accessing this playlist: https://www.youtube.com/playlist?list=PLFM03zQeSz2PvB2IxWqcLcZMSIIpcIVtV

How do you simplify \log_{5} ( b^{2} a^{8} )\log_{5} ( b^{2} a^{8} )?