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How do you factor $12 x^{3} - 40 x^{2} + 12 x$ $12x^{3} - 40x^{2} + 12x$ ?

1 Answer

Oct 9, 2016

$4 x (3 x - 1) (x - 3)$ $4x(3x-1 )(x-3)$

Explanation:

The first step of factoring is finding a GCF. In this case, the GCF is 4x. So factor out 4x from the expression: $4 x (3 x^{2} - 10 x + 3)$ $4x(3x^2-10x+3)$
Next, factor the trinomial:
$4 x (3 x - 1) (x - 3)$ $4x(3x-1 )(x-3)$

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