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How do you solve $3 {(y - 8)}^{2} = 96$ $3( y - 8)^{2} = 96$ ?

1 Answer

Oct 9, 2016

$y = 8 + 4 \sqrt 2, 8 - 4 \sqrt 2$ $y=8+4√2, 8-4√2$

Explanation:

Divide both sides of the equation by 3: ${(y - 8)}^{2} = 32$ $(y-8)^2=32$
Take the square root of both sides of the equation : $y - 8 = 4 \sqrt 2, y - 8 = - 4 \sqrt 2$ $y-8=4√2, y-8=-4√2$
Add 8 to both sides of both equations: $y = 8 + 4 \sqrt 2, y = 8 - 4 \sqrt 2$ $y=8+4√2, y=8-4√2$

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