How do you solve #3( y - 8)^{2} = 96#?

1 Answer
michael
Oct 9, 2016

#y=8+4√2, 8-4√2#

Explanation:

  1. Divide both sides of the equation by 3: #(y-8)^2=32#
  2. Take the square root of both sides of the equation : #y-8=4√2, y-8=-4√2#
  3. Add 8 to both sides of both equations: #y=8+4√2, y=8-4√2#
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