Question

How do you prove that the limit of `(x^2+3x)=-18` as x approaches -3 using the epsilon delta proof?

Answer 1

You can't. The limit is not `-18`.

Explanation:

`lim_(xrarr-3)(x^2+3x) = (-3)^2+3(-3) = 9-9=0`

graph{x^2 + 3 x [-10, 10, -5, 5]}