How do you differentiate #f(x)=sqrt30#?

1 Answer
Oct 11, 2016

0

Explanation:

If we consider that for any constant ( a value that does not contain some variable) that comprises a function that is to be derived, that constant is eliminated in the derivation process.

As such, if we consider the general parabolic function;
#f(x)=ax^2+bx+c#

Its derivative may be expressed as;

#f'(x)=2ax+b#

Note that the constant has been eliminated from the expression - effectively giving it a value of zero.

Thus, graphically, as #f'(x)=sqrt30# is a straight line with a gradient of zero - its derivative across the domain #R# must also be zero.