How do you find #(dy)/(dx)# given #x^2+y^2=1#?
1 Answer
Explanation:
Differentiate wrt
We already know how to deal with the first and third terms, so lets get them out the way:
For the remaining term we use the chain rule, we don't know how to differentiate
We can know perform that final differentiation, as we are now differentiating a function of
We can then rearrange to get