How do you solve $- 90 = 2 (y + - 92)$ $-90= 2( y + - 92)$ ?

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Answer 1 · 2016-10-12T15:46:23

$y = 47$ $y=47$

$1$ $1$ . Distribute 2 across the bracket:

$- 90 = 2 (y + - 92) \to - 90 = 2 y - 184$ $-90=2(y+ -92) rarr -90=2y-184$

$2$ $2$ . Add $184$ $184" "$ to each side

$- 90 + 184 = 2 y - 184 + 184 \to 94 = 2 y$ $-90+184 =2y-184+184 rarr 94=2y$

$3 .$ $3.$ Divide through by $2$ $2$

$94 = 2 y$ $94=2y$

$\to 47 = y$ $rarr 47=y$

How do you solve −90=2(y+−92)-90= 2( y + - 92)?