How do you solve $\frac { 6x - 8} { 7} = - 1$ ?

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Answer 1 · 2016-10-18T20:57:52

the answer is $x = 1/6$

First you multiply both sides of the equation by 7 to clear the fraction so

$(7xx(6x-8))/7 = (7)(-1)$
which gives

$6x-8 = -7$

then you add $8$ to both sides to begin isolating the x-value

$6x = -7+8$ which gives

$6x = 1$

then divide by $6$ to totally isolate the x

$(6x)/6 = 1/6$

or

$x = 1/6$

How do you solve \frac { 6x - 8} { 7} = - 1\frac { 6x - 8} { 7} = - 1?