Question

How do you solve `log_4 5 - log_4 (-4x)=1`?

Answer 1

`x = - 5/16`

Explanation:

`log_4 5 - log_4 (-4x) = 1`

`log_4 5 - log_4 (-4x) = log_4 4`

`log_4 (5/(-4x)) = log_4 4`

`(5/(-4x)) = 4`

`x = -5/16`