How do you solve $9y - 3( y - 3) = 27$ ?

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Answer 1 · 2016-10-21T00:27:12

The solution of the equation is $y = 3$ .

Begin by distributing the $-3$ . Then use inverse operations to solve the equation for $y$ .

$9y - 3(y - 3) = 27$
$9y -3y + 9 = 27$
$6y + 9 = 27$
$6y +9 - 9 = 27 - 9$
$6y = 18$
$(6y)/6 = 18/6$
$y = 3$

How do you solve 9y - 3( y - 3) = 279y - 3( y - 3) = 27?