How do you solve #4x + 8= 48#?

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Answer 1 · 2016-10-22T07:14:31

# color(red)(x = 10 #

# 4x + 8 = 48 #

Subtract 8 from each side, giving;

# 4x + 8color(red)(-8) = 48 color(red)(-8) #

# 4x = 40 #

Divide by 4 from each side, giving;

# (4x)/color(red)4 = 40/color(red)4#

#x = 10#

# color(blue)(Check;#
#= 4(10) + 8#
#= 40 + 8#
#= 48#