Question #2e4a2

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Question #2e4a2

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Answer 1 · 2016-10-23T04:50:09

$1.81$ $1.81$ x $10^{24}$ $10^24$ atoms (3 s.f.)

Explanation:

Recall that moles can be converted to particles using Avogadro's constant ( $6.022 \cdot 10^{23}$ $6.022*10^23$ ) which is the number of molecules per mole of a substance.

In $1.5$ $1.5$ moles of fluorine gas, there are $1.5 \cdot 6.022 \cdot 10^{23}$ $1.5*6.022*10^23$ molecules of gas. However, since fluorine is diatomic ( $F_{2}$ $F_2$ ), each molecule contains two atoms of fluorine. Thus, the number of atoms in $1.5 m o l$ $1.5 mol$ of $F_{2}$ $F_2$ is twice the number of molecules.

$:.$ No. of atoms $=2(1.5*6.022*10^23)=1.8066*10^24$

$=1.81*10^24$ (3 s.f.), since there are 3 s.f. in $1.50$ .

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