How do you solve each system by elimination 2x+3y=9, x+5y=8?

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Answer 1 · 2016-10-25T16:08:37

#x=3, y=1#

#2x+3y = 9 " and " x +5y= 8#

#x=8-5y# is inserted in the first equation,

#2(8-5y)+3y=9# then remove the bracket:,

#16-10y+3y=9#, then simplify:

#-7y=-7#, divide by #(-7)#

gives #y=1#

and #x=8-5=3#