How do you solve #3+e^(-2x)=8#?

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Answer 1 · 2016-10-30T19:29:37

So, you've got:

#3+e^(-2x)=8#

Now subtract 3 from both sides of the equation:

#e^(-2x)=5#

From here you get:

#-2x=ln(5)#

Now divide both sides of the equation by -2:

#x=-1/2*ln(5)#

This is your answer.