How do you differentiate #ln((sin^2)x)#?
2 Answers
Oct 30, 2016
Rewrite it first.
Explanation:
Now use
# = 2(1/sinx)*d/dx(sinx)#
# = 2(1/sinx) (cosx)#
# = 2cotx#
Oct 30, 2016
Which means that:
Use implicit differentiation on the left hand side of the equation and the chain rule on the right hand side of the equation:
Divide expressions on both sides of the equation by
Don't forget that
Simplify the fraction above:
Presto!!