How do you solve $126 \leq 7 (8 + 5 x)$ $126\leq 7( 8+ 5x )$ ?

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Answer 1 · 2016-10-31T16:08:47

$x \geq 2$ $x >= 2$

$7 (8 + 5 x) \geq 126$ $7(8+5x) >=126" "$ divide each side by 7, we get

$8 + 5 x \geq 18$ $8+5x >= 18" "$ subtract 8 from each side

$5 x \geq 10$ $5x >= 10" "$ divide each side by 5: we get

$x \geq 2$ $x >= 2$ .

How do you solve 126\leq 7( 8+ 5x )126≤7(8+5x)126\leq 7( 8+ 5x )?