Question #1e174 Calculus Basic Differentiation Rules Chain Rule 1 Answer Tiago Hands Nov 1, 2016 #y=1/(sqrt(2x-1))# #y^-1=sqrt(2x-1)# #y^-2=2x-1# Use implicit differentiation... #-2y^-3*(dy)/(dx)=2# #-y^-3*(dy)/(dx)=1# #-1/y^3*(dy)/(dx)=1# Multiply both sides of the equation by #-y^3#... #(dy)/(dx)=-y^3# #(dy)/(dx)=-(1/(sqrt(2x-1)))^3# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1436 views around the world You can reuse this answer Creative Commons License